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Research Topic: Six Sided Dice Result Distribution

By Ian Mander BSc, 19 February 1999, updated 15 August 1999.

Question: How do you work out how many ways there are of making any particular number when throwing a given number of [six sided] dice?

Answer: When one adds another die, each previous result has six new ways to be used. Therefore, one easy way to calculate the results is to use tables (such as a spreadsheet) to progressively sum for greater numbers of dice. The tables given below should be reasonably self-explanatory.

Each possible outcome total (for the number of dice being thrown - eg, you can throw anything from 2 to 12 inclusive for two dice) has a light blue background.

The number of ways of getting each outcome has a pale yellow background, and it's this line that's fed into the next table in six different positions for the six different ways the new die can be thrown.

Observation: The more dice one throws at one time, the closer the result distribution approximates a normal distribution. As can be seen by the graphs below, anything from three dice upwards gives a reasonably close approximation to a normal distribution.


One die:

1
1
1
1
1
1
1 1 1 1 1 1
1 2 3 4 5 6


Two dice:
1 1 1 1 1 1
1 1 1 1 1 1
1 1 1 1 1 1
1 1 1 1 1 1
1 1 1 1 1 1
1 1 1 1 1 1
1 2 3 4 5 6 5 4 3 2 1
2 3 4 5 6 7 8 9 10 11 12


Three dice:

1 2 3 4 5 6 5 4 3 2 1
1 2 3 4 5 6 5 4 3 2 1
1 2 3 4 5 6 5 4 3 2 1
1 2 3 4 5 6 5 4 3 2 1
1 2 3 4 5 6 5 4 3 2 1
1 2 3 4 5 6 5 4 3 2 1
1 3 6 10 15 21 25 27 27 25 21 15 10 6 3 1
3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18


Four dice:

1 3 6 10 15 21 25 27 27 25 21 15 10 6 3 1
1 3 6 10 15 21 25 27 27 25 21 15 10 6 3 1
1 3 6 10 15 21 25 27 27 25 21 15 10 6 3 1
1 3 6 10 15 21 25 27 27 25 21 15 10 6 3 1
1 3 6 10 15 21 25 27 27 25 21 15 10 6 3 1
1 3 6 10 15 21 25 27 27 25 21 15 10 6 3 1
1 4 10 20 35 56 80 104 125 140 146 140 125 104 80 56 35 20 10 4 1
4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24



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