Research Topic: Normally Distributed Percentile Dice
By Ian Mander BSc, written 29 May 2016, posted 14 November 2018.
Question: What is the best way of getting a normally distributed percentile die roll? (In other words, using dice to make a number from 0-100, with a mean, median, and mode of 50, with the middle numbers having a greater probability of occurring, in a normally distributed bell curve.) If we include rolls that give a 1-100 result, or even narrower ranges, non-continuous ranges, are there any interesting (or convenient) rolls?
Answer: In a previous research topic Six Sided Dice Roll Distribution we see that a bell curve that approximates a normal distribution needs at least three dice. The more dice used the narrower the curve and the less likely a low or high result is. This implies the best rolls will likely use three or four dice.
This tool graphs some of the best approximations and allows others to be tested.
The first option, 3d30+4, doesn't have much going for it. There are options with a wider range. The dice can be found in eBay.
A 4d24 roll gives results from 4 to 96 with a single mode. It's very simple since no modification is needed and gives almost the full range of percentile results. 24 sided dice are available on eBay with only a small amount of searching, in two different forms.
The next option, 5d20-2, has a slightly wider range and uses more common 20-sided dice. Downsides are it's bimodal and it has a narrower peak than 4d24.
A very interesting option is 4d6*5-20 which gives a non-continuous distribution with possible totals every fifth number. The dice are very common and the maths is simple enough to do in one's head.
If we are going to limit ourselves to using real dice, the simplest way of getting a 1-100 bimodal result is 3d34-2. It gives a range of 1-100 with a good chance of low and high results. Unfortunately, while they do exist, 34-sided dice are extremely hard to find. They are an unusual shape for dice, being bipyramidal.
The next simplest is 3d100/3. This is the average of three d100 rolls, each using a pair of reasonably commonly available 10-sided percentile dice (which themselves give a flat distribution). It gives a very similar 1-100 bimodal result to 3d34-2 but is more difficult to work out.
Because 11d10-10 and 20d6-20 use so many dice they both have a very narrow peak.
Note – d10 assumed to give a result 1-10, not 0-9.
A 0-100 single mode distribution is possible in a number of ways from "virtual" dice – dice which are easy to calculate on a computer with a random number generator, but which don't actually exist.
The simplest way is to take the number of dice in the roll as a factor of 100, the number of sides for each die one more than the factor pair of the first factor, and for a modifier subtract the number of dice. If x * y = 100, the roll is xd(y+1)–x. This effectively gives x dice each providing 0-y.
For example, 4 * 25 = 100. Take 4 as the number of dice, 25 + 1 = 26 sides per die, and subtract 4, the number of dice: 4d26-4.
4d26-4 has a wide spread.
5d21-5 has a slightly narrower spread.
10d11-10 is getting quite narrow. Interestingly, 10d11-10 gives a 0-100 result but 11d10-10 (listed above) gives a 1-100 result.
20d6-20 is an example of this sort of calculation using real dice; it's listed above.
25d5-25 is very narrow.
50d3-50 is extremely narrow.
100d2-100 is crazy narrow, almost no chance of a result outside of 30-70. This roll is the equivalent of tossing 100 coins, each with the two sides labelled 0 and 1.
Sorry, some figures missing from that table still.